Frequenze proprie della corda en

From "Physics, Waves, Music": a website about the physics of waves and sound, acoustics of musical instruments, musical scales, harmony and music.

AI-translated from Italian. Original page: Frequenze_proprie_della_corda

Definitions and approximations

By ideal string, in this context, we mean a one-dimensional, perfectly flexible object.

The parameters describing an ideal string are summarised in the following table:

symbol meaning SI unit
L length of the string m
T tension of the string N
μ linear density of the string kg m-1

When studying the physics of real objects, we must find conditions that approximate the ideal ones.

  • An object much longer than its diameter approximates the condition of one-dimensionality, provided that the motion of the string about its axis (torsion) can be neglected.
  • The condition that the string is perfectly flexible can reasonably be assumed if the bending stiffness and all external forces are negligible compared with the tension.
  • Moreover, the tension is assumed not to change much during the motion of the string, that is, not to depend on the amplitude of the oscillation. This condition is generally met only for small displacements from equilibrium.
  • The bending stiffness, negligible at low frequencies, matters more and more as the frequency increases: for frequencies that are "not too high" the string therefore behaves as an ideal string (see the page wave equation for the string).

When a real string departs from these conditions, the results given here of course do not hold, and more complex models are needed (for example, stiffness makes the higher frequencies slightly sharper than integer multiples of the fundamental: this is the inharmonicity of strings).

Transverse vibrations of the ideal string fixed at both ends

The fundamental frequency of an ideal string fixed at both ends is given by

f0=12LTμ.

The higher frequencies are integer multiples of its fundamental frequency f0

fn=nf0n=1,2,….

How are these values calculated?

We can follow two equivalent routes:

  1. solve the wave equation with the boundary conditions describing the string fixed at both ends, namely that the displacement of the string is zero at the ends (see wave equation)
  2. study the normal modes of the string (see normal modes and normal modes of a string)

Natural frequencies of the string in the presence of friction

In the section wave equation we briefly described the wave equation in the presence of friction, and its general travelling solution. Here we are interested in the stationary solutions, whose frequencies correspond to the natural frequencies of the string. Calling γ the friction coefficient, we get

fn=12ππ2TL2μn2−γ24

Note that, for the same mode (the integer n), the frequency with friction is slightly lower than that of the string without friction.

String instruments

physics of string instruments

Further reading and links

Check your understanding

Problem. The A4 string of a violin (440 Hz) has a vibrating length of 33 cm and a linear density of 0.6 g/m. What tension is needed to tune it? Solution. From the formula for the fundamental T=μ(2Lf0)2 = 0.0006 · (2 · 0.33 · 440)² N ≈ 0.0006 · 290² N ≈ 51 N, about the weight of a 5 kg mass.

Problem. We want to raise the note of a string by an octave by acting only on the tension. By how much must it be increased? Why, in practice, is the string shortened instead (by pressing it against the fingerboard)? Solution. The frequency is proportional to T: to double it, the tension must become four times larger, an increase that the string would hardly withstand. Halving the length, instead, doubles the frequency without changing the tension.

Problem. A string has a fundamental of 100 Hz and a friction coefficient γ = 1 s−1. By how much does friction lower the frequency? (Remember that in the telegraph equation the amplitude decreases as exp⁡(−γt/2).) Solution. The first term under the square root is (2πf1)2 ≈ 395000 s−2, while γ2/4 = 0.25 s−2: the frequency decreases by a fraction γ2/(8ω2) ≈ 3·10−7, completely negligible. Yet the amplitude already halves after 2ln⁡2/γ ≈ 1.4 s: friction damps the string long before it detunes it.


"Physics, Waves, Music": a website about the physics of waves, acoustics of musical instruments, musical scales, harmony and music.