Distorsione di intermodulazione en

From "Physics, Waves, Music": a website about the physics of waves and sound, acoustics of musical instruments, musical scales, harmony and music.

AI-translated from Italian. Original page: Distorsione_di_intermodulazione
  • In an ideal, perfectly linear system, a monochromatic signal, that is, one made of a single sinusoidal component at frequency f0, can only be changed into another monochromatic signal at the same frequency.
  • If instead the system shows non-linear effects, which always happens for large enough amplitudes of the input signal, it can distort the signal, which simply means introducing new harmonics that do not belong to the spectrum of the original signal.
  • An easy example of distortion occurs when a piece of music is played too loud (or at normal volume, but on low-quality equipment). The signal is "clipped" or flattened at its extremes, so the output signal is no longer a faithful reproduction of the input signal. Essentially, the main aim of high fidelity is to ensure a response that is as linear as possible over the widest range of frequencies and intensities of the input signal.
  • Intermodulation, however, can also be exploited usefully to "enrich" with harmonics a musical sample whose sound would otherwise be "flat".
  • You can experience the effect of clipping distortion directly with the "Aumenta e taglia" (amplify and clip) function of the Fourier app. For a guide, see experiments on distortion.

Intermodulation in radio and in the human ear

In the simplest case, intermodulation distortion arises from the non-linear combination of two sinusoids. One operation that produces this combination is multiplying the signals together. Recall, in fact, that the only operations allowed by a linear transformation are the algebraic sum of signals and the multiplication of signals by a constant. Multiplying signals together, instead, produces components with frequencies equal to the sum and difference of the initial frequencies, as can be seen immediately from the following trigonometric identity:

sin⁡(ω1t)cos⁡(ω2t)=12sin⁡[(ω1+ω2)t]+12sin⁡[(ω1−ω2)t].

A non-linear system produces these products even without an actual multiplier. If, for example, the output y contains, besides a term proportional to the input x, a small quadratic term,

y=ax+bx2,

and the input is the sum of two sinusoids, x=sin⁡(ω1t)+sin⁡(ω2t), the term x2 contains the product

2sin⁡(ω1t)sin⁡(ω2t)=cos⁡[(ω1−ω2)t]−cos⁡[(ω1+ω2)t],

that is, the difference and sum frequencies. The other two terms of x2, sin2(ω1t) and sin2(ω2t), produce the doubled frequencies 2f1 and 2f2 and a constant component.

In radio this operation is performed in order to transmit (modulate) an audio signal, that is, one at acoustic frequencies, on an electromagnetic carrier at radio frequency. Several annotated examples can be found on the page on radio.

In the human ear, a multiplication of this kind seems to take place when intense signals are received. The ear therefore does not simply record and faithfully reproduce what it receives from outside, but adds new harmonic components to the sound, which in some cases can be perceived as extraneous sounds. On this subject see the pages on acoustic effects and illusions and on beats.

Check your understanding

Problem. Two pure tones of 1000 Hz and 1200 Hz enter an amplifier whose response contains a small quadratic term, y=ax+bx2. Which frequencies appear at the output? Solution. Besides the original frequencies, 1000 Hz and 1200 Hz (from the linear term), the quadratic term produces the difference 1200 − 1000 = 200 Hz, the sum 2200 Hz, the doubled frequencies 2000 Hz and 2400 Hz, and a constant component (0 Hz). The 200 Hz component lies very far from the original sounds and is particularly easy to hear.

Problem. Two violins play loudly an A5 (880 Hz) and a C♯6 (1100 Hz), that is a major third (ratio 5:4). Many listeners also hear a lower sound that nobody is playing. What is its frequency? Solution. It is the difference tone, produced by the non-linearity of the ear with intense signals: 1100 − 880 = 220 Hz, that is an A3, two octaves below the A5. It is the "third sound" described by Giuseppe Tartini in the 18th century.

Problem. An amplitude-modulation radio station transmits on a carrier at 1000 kHz. Which frequencies does it emit when it transmits a pure 1 kHz tone? What frequency band does it occupy if it transmits music with frequencies up to 5 kHz? Solution. Multiplying the carrier by the audio signal produces the sum and difference frequencies: 1001 kHz and 999 kHz (besides the carrier itself). With an audio signal up to 5 kHz the station occupies the band from 995 kHz to 1005 kHz, 10 kHz wide: this is why medium-wave stations must be spaced about 10 kHz apart.


"Physics, Waves, Music": a website about the physics of waves, acoustics of musical instruments, musical scales, harmony and music.